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From YouTube: inverse-theory-part-3
Description
LAPIS 2019
A
A
Problem,
don't
whine
we're
gonna
sit
properly.
Rated
right
deal
is
equal
to
just
on
matrix
g
r3
yeah.
We
had
a
quadratic
regularization
and
it
looks
like-
and
we
just
solved
this
in
one
step,
so
we
still
have
this
private
baby
interview
with
the
baby
secret
for
18
solving
one-step.
So
the
problem,
however,
becomes
nonlinear.
A
A
A
A
When
you
get
two
frogs
like
that,
that's
that
could
be
really
challenging,
because,
thankfully,
and
on
where
you
are,
this
is
how
work
are
you
to
start
we're
going
to
and
actually
kind
of
works
with
the
starting
position?
Someplace?
That
is
wherever
and
we're
just
going
to
basically
try
to
find
the
nearest
local
trying
to
do
global
problems
in
which
you
find
you
know.
The
global
minimum
of
things
is
a
whole
entirely
different
process
than
anything.
A
So
how
do
we
give
it
I?
Suppose
it's
something
look
like
this,
then,
what's
the
procedure
for
getting
here
when
we're
starting,
you
start
here,
and
so,
let's
suppose,
we're
at
the
solution,
and
then
we
want
find
a
purty
Delta
X
that
takes
us
closer
for
two
bits
to
this.
Now,
that's
our
goal
right
here
want
to
end
up
there.
A
A
A
A
A
A
A
A
So
how
do
we
do
this?
Well,
let's
begin
with
the
solution.
Let's
begin
with
and
suffocate
replication
iteration,
and
then
we're
going
to
call
this
main
research
term,
H
Delta
M
is
equal
to
the
minus
the
gradient.
So
this
is
this
is
exactly
it
makes
you
supply
rather
f,
prime
prime
Delta
X,
so
that's
like
H,
ok,
Delta,
M
and
then
minus
G,
which
is
my
prime.
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
Relations
so
dc-dc
resistivity
actual
operations
zero.
Previously
we
end
up
with,
given
that
Phi
is
equal
to
current
we're
going
to
inject
a
current
and
here's
the
Delta
function,
so
it
just
means
were
injecting
a
V
is
cranking.
The
electric
potential
and
treatment
is
to
be
funny,
so
our
equation
that
we
need
that
we
want
to
solve
so
whether
the
old
name
is
equal
to
e
that
the
and.
A
A
Basis
of
plaster
and
we're
going
to
use
the
finite
volume
technique,
discretized
equations,
so
that
you
can
make
this
and
basically
represent
that
in
a
matrix
form
that
looks
like
this.
So
now,
G
is
a
gradient
operator.
It's
not
that
full
for
Jesus
breeding
and
yeah,
a
mass
matrix
that
depends
upon
the
electrical
conductivity
and
G
transpose,
is
divergent
attention
transfer.
A
A
A
A
A
Solver
or
and
okay,
so
we've
got
solved
it.
We
need
to
compute
the
matrix
J
and
now
there's
question
goes
okay.
How
do
we
do
that?
That's
not
that's!
It
Denis
me
to
promise
of
challenge
yeah.
So
let
me
just
kind
of
walk
you
through
the
pieces.
I,
look
we're
not.
You
did
all
the
details,
but
you
like
the
item
and
the
idea
and
really.
A
A
A
A
A
A
A
A
A
We're
going
to
multiply
the
speaker's
here
on
the
right
hand,
side
so
distance
in
the
desert
and
animals.
We
need
to
multiply
disappear,
and
that
means
we
need
to
be
able
to
gain
times
the
vector
with
Jane,
it's
good
operating
picture
and
then
craft
both
so
that
both
we
are
in
that
we
remember.
Jane
was
just
like
there
and
all
these
units
is
response.
A
A
A
Turns
out
through
TV
series,
acidity
problem,
we've
got
a
conductive
block,
was
here
and
pretty
years,
an
array
where
we
got
electric
dipoles
for
current
and
potential
supers
and
here's
our
apparently
distributing
intersection
so
breach
data.
We
try
to
find
the
homogeneous
acts.
Things
like
if
drive.
A
A
First
generation
were
very
big
and
very
small
model
morning
and
here's
the
predicted
long
so
as
this
kind
of
got
a
little
bit
of
chili
and
let's
get
original
generation,
three
complexity
pull
out
a
little
bit
more
sorry,
there
is
an
creep
see
we're
here.
So
do
a
little
bit
better
and
iteration
for
here
at
Barry's
apartment,
so
sweet
syrup,
XR,
5,
iteration,.
A
A
A
So
that's
that's
sort
of
the
end
result,
and
this
is
kind
of
rated
like
India
to
sometimes.
Luckily
it
looks
a
bit
more
geologic
and
in
fact,
in
this
case
see
it's
really
quite
accessible,
illuminating
this
black
chain
aluminum.
It
turns
out
for
this
particular
example.
That's
a
mom
exactly
one
with
a
spot
from
the
point
of
view
of
mineralization.